Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 373: 23

Answer

(32$\pi$ - 64)$in^{2}$

Work Step by Step

In the circle diameter of the circle = diagonal of the square By pythagoras theorem $diagonal^{2}$ = $8^{2}$ + $8^{2}$ $diagonal^{2}$ = 64 + 64 diagonal = $\sqrt 128 $ = 8$\sqrt 2$ in Therefore the diameter of the circle = 8$\sqrt 2$ in Area of the circle = $\pi r^{2}$ = $\pi (4\sqrt 2)^{2}$ = 32$\pi in^{2}$ Area of square = $s^{2}$ = $8^{2}$ = 64 $in^{2}$ Therefore the shaded area = (32$\pi$ - 64)$in^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.