Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 367: 34


Between 49 and 77

Work Step by Step

We find the area of the circle: $ A = \pi r^2 = \pi(3.5\sqrt{2})^2 \approx 77$ We find the area of the square. Since each triangle formed is a 45-45-90 triangle, we obtain that if the diagonal has length $3.5\sqrt2$, the sides must have length 7. Thus: $A = 7^2 = 49$
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