## Elementary Geometry for College Students (6th Edition)

12 $ft^{2}$
Given Altitude length of trapezoid = 5$\frac{1}{3}$ ft the length of the median of the trapezoid = 2$\frac{1}{4}$ft We know the area of the trapezoid whose altitude has length h and whose median has length m is A= hm therefore Area of trapezoid = hm = 5$\frac{1}{3}$ ft * 2$\frac{1}{4}$ft = $\frac{16}{3}$ * $\frac{9}{4}$ = 12 $ft^{2}$