Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 7 - Section 7.3 - More about Regular Polygons - Exercises - Page 333: 22

Answer

(a) $120^{\circ}$ (b) $90^{\circ}$

Work Step by Step

(a) We can find the number of vertices of the polygon: $60^{\circ} = \frac{360^{\circ}}{n}$ $n = \frac{360^{\circ}}{60^{\circ}}$ $n = 6$ We can find the interior angle of this polygon: $\frac{(n-2)(180^{\circ})}{n} = \frac{(6-2)(180^{\circ})}{6} = 120^{\circ}$ (b) We can find the number of vertices of the polygon: $90^{\circ} = \frac{360^{\circ}}{n}$ $n = \frac{360^{\circ}}{90^{\circ}}$ $n = 4$ We can find the interior angle of this polygon: $\frac{(n-2)(180^{\circ})}{n} = \frac{(4-2)(180^{\circ})}{4} = 90^{\circ}$
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