Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 7 - Section 7.3 - More about Regular Polygons - Exercises - Page 333: 31

Answer

m$\angle$VPS=168$^{\circ}$

Work Step by Step

The interior angles of a regular pentagon have a measure of 108 degrees. m$\angle$VQP=108-m$\angle$PQR m$\angle$VQP=108-60=48 m$\angle$VPQ=.5(180-m$\angle$VQP) m$\angle$VPQ=.5(132)=66 m$\angle$RPS=m$\angle$VPQ=66 m$\angle$VPS=360-m$\angle$RPS-m$\angle$VPQ-m$\angle$QPR m$\angle$VPS=360-66-66-60 m$\angle$VPS=168$^{\circ}$
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