Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Test - Page 264: 7a


$c=\sqrt 41$

Work Step by Step

Using Pythagorean's Theorem... $a^{2}+b^{2}=c^{2}$ Substitute in known lengths... $5^{2}+4^{2}=c^{2}$ Simplify... $25+15=c^{2}$ $41=c^{2}$ Square root both sides... $\sqrt 41=c$
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