#### Answer

$c=\sqrt 41$

#### Work Step by Step

Using Pythagorean's Theorem...
$a^{2}+b^{2}=c^{2}$
Substitute in known lengths...
$5^{2}+4^{2}=c^{2}$
Simplify...
$25+15=c^{2}$
$41=c^{2}$
Square root both sides...
$\sqrt 41=c$

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Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

$c=\sqrt 41$

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