Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Test - Page 264: 2b


$x=9, x=-9$

Work Step by Step

$\frac {x+1}{5}=\frac {16}{x-1}$ Cross Multiply... $(x+1)(x-1)=5(16)$ Simplify by multiplying $x^{2}+1x-1x-1=80$ $x^{2}-1=80$ Add 1 to both sides... $x^{2}=81$ Square root both sides... $x=9, x=-9$
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