Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 247: 7


$XZ = 10$ $YZ= 10$

Work Step by Step

By the given Figure $\angle Z=90^{\circ}$ given $\angle X=45^{\circ}$ given So remaining$ \angle Y=45^{\circ}$ now $XY= 10 \sqrt 2$ given By Theorem 5.5.1/ (45-45-90 Theorem) $XZ = 10$ $YZ= 10$
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