Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 247: 5


YZ = 8 XY= 8$\sqrt 2$

Work Step by Step

By the given Figure $\angle Z=90^{\circ}$ given $\angle X = 45^{\circ}$ given So remaining $\angle Y = 45^{\circ}$ now XZ = 8 given YZ = 8 XY= 8$\sqrt 2$ By Theorem 5.5.1/ (45-45-90 Theorem)
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