## Elementary Geometry for College Students (6th Edition)

By using the same process that we used in excercise 30 which is applying the pythagorean theorem in each small triangle then create a system of equation. We obtain two pythagorean equations : $10^{2} = ( y-26 )^{2}+ h^{2}$ $24^{2}=y^{2}+h^{2}$ Therefore $y= \frac{120}{13}$ By substituting $y$ in one of the equation above Then the $h= \frac{288}{13}\approx 9.2$