Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 241: 27

Answer

Hypotenuse = 12 in.

Work Step by Step

By Pythagoras Theorem $Hypotenuse^{2}=(6\sqrt 2)^{2}+(6\sqrt 2)^{2}$ $Hypotenuse^{2}=72+72$ $Hypotenuse^{2}=144$ Hypotenuse = 12 in.
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