Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.3 - Proving Triangles Similar - Exercises - Page 232: 29

Answer

EB=24

Work Step by Step

$\frac{CB}{CD}$=$\frac{CA}{CE}$ $\frac{EB+6}{10}$=$\frac{18}{6}$ EB+6=30 EB=24
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