Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.3 - Proving Triangles Similar - Exercises - Page 232: 29



Work Step by Step

$\frac{CB}{CD}$=$\frac{CA}{CE}$ $\frac{EB+6}{10}$=$\frac{18}{6}$ EB+6=30 EB=24
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