Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.3 - Proving Triangles Similar - Exercises - Page 232: 26

Answer

DE=5

Work Step by Step

$\frac{DE}{AC}$=$\frac{EB}{CB}$ $\frac{DE}{10}$=$\frac{6}{12}$ 2DE=10 DE=5
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