## Elementary Geometry for College Students (6th Edition)

1- Given $\overline{AB} \parallel \overline{DF}$ 2- $\angle A = \angle E$ ( corresponding angles of two parallel lines cut by a transversal are congruent ) 3- Given $\overline{BD} \parallel \overline{FG}$ 4- $\angle ABC = \angle EFG$ by the same Reason as step two. 5- $\triangle ABC \triangle EFG$ are similar by AA