Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.3 - Proving Lines Parallel - Exercises - Page 233: 38

Answer

AE=8$\frac{4}{7}$

Work Step by Step

$\frac{AE}{AF}$=$\frac{AD}{AB}$ $\frac{AE}{5}$=$\frac{12}{7}$ 7AE=60 AE=8$\frac{4}{7}$
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