Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 224: 38

Answer

The ideal viewing distance is about 10 feet.

Work Step by Step

We can find the ideal viewing distance $V$: $D = 4.3~V$ $V = \frac{D}{4.3}$ $V = \frac{42}{4.3}$ $V \approx 10~ft $ The ideal viewing distance is about 10 feet.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.