Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 224: 24

Answer

AE$\approx$6.7

Work Step by Step

$\frac{AE}{AC}$=$\frac{AD}{AD+AE}$ $\frac{AE}{18}$=$\frac{4}{4+AE}$ AE$^2$+4AE-72=0 AE=$\frac{-4+\sqrt {16+288}}{2}$ AE=-2+.5$\sqrt {304}$ AE$\approx$6.7
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