## Elementary Geometry for College Students (6th Edition)

$n=3$
Since the quadrilaterals are similar, the corresponding sides will be proportional. So, set up a proportion... $\frac{AB}{HJ}=\frac{BC}{JK}$ Substitute in the appropriate values... $\frac{5}{10}=\frac{n}{n+3}$ Cross multiply... $5(n+3)=10(n)$ Distribute the five... $5n+15=10n$ Subtract $5n$ from both sides... $15=5n$ Divide by five... $n=3$