Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 223: 14

Answer

HJ=3$\frac{3}{4}$

Work Step by Step

$\frac{HK}{KF}$=$\frac{6}{8}$=$\frac{3}{4}$ $\frac{HJ}{FG}$=$\frac{HK}{KF}$ $\frac{HJ}{5}$=$\frac{3}{4}$ 4HJ=15 HJ=3$\frac{3}{4}$
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