Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.1 - Ratios, Rates, and Proportions - Exercises - Page 216: 21


a) $AD=4\sqrt {3}$ b) $BD=4.5$

Work Step by Step

a) $\frac{AD}{BD}=\frac{DC}{AD}$ $\frac{AD}{6}=\frac{8}{AD}$ $AD^{2}=8\times6$ $AD^{2}=48$ $AD=\sqrt {48}$ $AD=4\sqrt {3}$ b) $\frac{AD}{BD}=\frac{DC}{AD}$ $\frac{6}{BD}=\frac{8}{6}$ $6\times6=8BD$ $36=8BD$ $BD=\frac{9}{2}=4.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.