Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.1 - Ratios, Rates, and Proportions - Exercises - Page 216: 10b


$x=-8$ or $8$

Work Step by Step

$\frac{x-2}{5} = \frac{12}{x+2}$ $(x-2)(x+2) = 12\times5$ $x^{2}-4 = 60$ $x^{2}-64 = 0$ $(x+8)(x-8) = 0$ $x=-8$ or $8$
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