Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 3 - Section 3.2 - Corresponding Parts of Congruent Triangles - Exercises - Page 138: 38


Alinna traveled 4 miles farther by using alternative route from A to B

Work Step by Step

According to question AC=5 miles and CB=12 miles $\triangle$ABC is right angled triangle $AB^{2}$=$AC^{2}$+$CB^{2}$ $AB^{2}$=$5^{2}$+$12^{2}$ $AB^{2}$=25+144 $AB^{2}$=169 AB=$\sqrt 169$=13 Now we have to find how much farther Alinna traveled so it will be, AC+CB-AB 5+12-13=4 miles
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.