Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 3 - Section 3.2 - Corresponding Parts of Congruent Triangles - Exercises - Page 138: 32

Answer

- From the given information, we can deduce $\angle 1\cong\angle 2$ and $\angle 3\cong\angle 4$ - Then, prove that $\triangle MQP\cong\triangle PNM$ by method ASA - Then, by CPCTC, $\overline{MQ}\cong\overline{PN}$

Work Step by Step

*PLANNING: - From the given information, we can deduce $\angle 1\cong\angle 2$ and $\angle 3\cong\angle 4$ - Then, prove that $\triangle MQP\cong\triangle PNM$ - Then, by CPCTC, $\overline{MQ}\cong\overline{PN}$ 1) $\overline{MN}\parallel\overline{QP}$ and $\overline{MQ}\parallel\overline{NP}$ (Given) 2) $\angle 1\cong\angle 2$ and $\angle 3\cong\angle 4$ (if 2 lines are parallel, then the alternate interior angles for these 2 lines are congruent) 3) $\overline{MP}\cong\overline{PM}$ (Identity) So now we have 2 angles and the included side of $\triangle MQP$ are congruent with 2 corresponding angles and the included side of $\triangle PNM$ 4) $\triangle MQP\cong\triangle PNM$ (ASA) 5) $\overline{MQ}\cong\overline{PN}$ (CPCTC)
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