Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 93: 26

Answer

$x=108^{\circ}$

Work Step by Step

$m\angle 1+m\angle 2=90^{\circ}$ Because complementary angles of a right triangle $x/2+x/3=90^{\circ}$ $5x/6=90^{\circ}$ $x=108^{\circ}$
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