Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 93: 22

Answer

x=90$^{\circ}$ m$\angle$BAC=90$^{\circ}$ m$\angle$B=45$^{\circ}$

Work Step by Step

m$\angle$B+m$\angle$C+m$\angle$BAC=180 $\frac{x}{2}$+$\frac{x}{2}$+x=180 4x=360 x=90$^{\circ}$ m$\angle$BAC=x=90$^{\circ}$ m$\angle$B=$\frac{x}{2}$=45$^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.