#### Answer

$9$

#### Work Step by Step

$\sin37^{\circ}=\frac{y}{15}$
$15\times\sin37^{\circ}=y$
$y\approx9$

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Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

$9$

$\sin37^{\circ}=\frac{y}{15}$
$15\times\sin37^{\circ}=y$
$y\approx9$

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