Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Test - Page 526: 3a

Answer

$1$

Work Step by Step

$\tan45^{\circ}=\frac{\sin45^{\circ}}{\cos45^{\circ}}$ $\tan45^{\circ}=\frac{\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}$ $\tan45^{\circ}=1$
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