Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 10 - Test - Page 488: 22

Answer

(a) $(x,y,z) = (-1,-9,20)$ (b) The point $(6,5,-12)$ does not lie on the line.

Work Step by Step

(a) We can find the point on the line when $r=-3$: $(x,y,z) = (2+r,-3+2r,5-5r)$ $(x,y,z) = (2+(-3),-3+2(-3),5-5(-3))$ $(x,y,z) = (-1,-9,20)$ (b) If the point $(6,5,-12)$ lies on the line, there is a real number $r$ such that $(x,y,z) = (2+r,-3+2r,5-5r) = (6,5,-12)$. x coordinate: If $2+r = 6$, then $r = 4$ y coordinate: If $-3+2r = 5$, then $r = 4$ z coordinate: If $5-5r = -12$, then $r = \frac{17}{5}$ Since the required value of $r$ is not the same for all three coordinates, the point $(6,5,-12)$ does not lie on the line.
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