## Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole

# Chapter 10 - Test - Page 488: 21

#### Answer

(a) The midpoint of the line segment $~\overline{P_1P_2}~$ is: $(0, 1, -1)$ (b) $d = 13.3$

#### Work Step by Step

$P_1 = (-2,3,5)$ $P_2 = (2,-1,-7)$ (a) We can find the midpoint between these two points: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} ,\frac{z_1+z_2}{2})$ $= (\frac{-2+2}{2},\frac{3+(-1)}{2} ,\frac{5+(-7)}{2})$ $= (0, 1, -1)$ The midpoint of the line segment $~\overline{P_1P_2}~$ is: $(0, 1, -1)$ (b) We can find the length $d$ of $\overline{P_1P_2}$: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$ $d = \sqrt{(2-(-2))^2+(-1-3)^2+(-7-5)^2}$ $d = \sqrt{(4)^2+(-4)^2+(-12)^2}$ $d = \sqrt{16+16+144}$ $d = \sqrt{176}$ $d = 13.3$

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