#### Answer

$y = cx + ({-ca+b})$

#### Work Step by Step

If the line is perpendicular to the line with slope -1/c, then its slope must be c. Using the point (a,b), we find:
$y-b=c(x-a)$
Simplifying to slope intercept form:
$y = cx-ca+b$
$y = cx + ({-ca+b})$