Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 10 - Test - Page 487: 10

Answer

$a=\sqrt{b^{2}+c^{2}}$

Work Step by Step

The length of AB can be calculated: $x_{B}-x{A}=a$ The length of AD can be calculated with the Pythagorean Theorem: $\sqrt{(x_{d}-x_{a})^{2}+(y_{d}-y_{a})^{2}} = \sqrt{(b-0)^{2}+(c-0)^{2}}$ So, $a=\sqrt{b^{2}+c^{2}}$
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