Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 472: 41

Answer

$(\frac{a-c}{b}, a)$

Work Step by Step

$y=a$ $y=bx+c$ In this problem we want to equate the two expressions for y and solve for x, while treating a, b, and c as constants. $a=bx+c$ $a-c=bx$ $x=\frac{a-c}{b}$ Since it is given in the problem that $y=a$, our answer is $(\frac{a-c}{b}, a)$.
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