## Elementary Geometry for College Students (6th Edition)

$(\frac{a-c}{b}, a)$
$y=a$ $y=bx+c$ In this problem we want to equate the two expressions for y and solve for x, while treating a, b, and c as constants. $a=bx+c$ $a-c=bx$ $x=\frac{a-c}{b}$ Since it is given in the problem that $y=a$, our answer is $(\frac{a-c}{b}, a)$.