Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 472: 39


(6, 0)

Work Step by Step

Equating the expressions for y: $\frac{1}{3}x-2=\frac{1}{2}x-3$ $1=\frac{1}{6}x$ $x=6$ Substituting $x=6$ into $y=\frac{1}{3}x-2$: $y=\frac{1}{3}*6-2$ $y=\frac{6}{3}-2$ $y=2-2$ $y=0$ So the answer is $(6, 0)$.
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