## Elementary Geometry for College Students (6th Edition)

Equating the expressions for y: $\frac{1}{3}x-2=\frac{1}{2}x-3$ $1=\frac{1}{6}x$ $x=6$ Substituting $x=6$ into $y=\frac{1}{3}x-2$: $y=\frac{1}{3}*6-2$ $y=\frac{6}{3}-2$ $y=2-2$ $y=0$ So the answer is $(6, 0)$.