Answer
$x_{1}=\sqrt{35}+3; y_{1}=0$
$x_{2}=-\sqrt{35}+3; y_{2}=0$
Work Step by Step
The two points are on the x axis, so
$y_{1}=y_{2}=0$
Using the Distance Formula we can calculate the distances.
$\sqrt{(x-3)^{2}+(0-1)^{2}} = \sqrt{(x-3)^{2}+1} = 6$
$(x-3)^{2}+1=36$
$(x-3)^{2}=35$
$(x-3) = \pm\sqrt{35}$
$x=\pm\sqrt{35}+3$
$x_{1}=\sqrt{35}+3$
$x_{2}=-\sqrt{35}+3$
