## Elementary Geometry for College Students (6th Edition)

$x_{1}= 0 ;y_{1}=\sqrt{27}+1$ $x_{2}= 0;y_{2}=-\sqrt{27}+1$
The two points are on the y axis, so $x_{1}=x_{2}=0$ Using the Distance Formula we can calculate the distances. $6 = \sqrt{(0-3)^{2}+(y-1)^{2}} = \sqrt{9+(y-1)^{2}}$ $9+(y-1)^{2}=36$ $(y-1)^{2}=27$ $(y-1) = \pm\sqrt{27}$ $y=\pm\sqrt{27}+1$ $y_{1}=\sqrt{27}+1$ $y_{2}=-\sqrt{27}+1$