Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 4 - Eigenvalues and Eigenvectors - 4.2 Determinants - Exercises 4.2 - Page 281: 15

Answer

$abgd$

Work Step by Step

First, use cofactor expansion (Theorem 4.1) along the third row because that is the row/column with the most zeros: \[ \begin{vmatrix} 0 & 0 & 0 & a\\0 & 0 & b & c\\0 & d & e & f\\g & h & i & j \end{vmatrix} = 0-0+0-a \cdot \begin{vmatrix} 0 & 0 & b\\0 & d & e\\g & h & i \end{vmatrix} \] Now expand along the first row again: =$-a \cdot (0-0+b \cdot \begin{vmatrix} 0 & d\\g & h \end{vmatrix} )$ Lastly, simplify the expansion: $=-a \cdot (b \cdot (0-gd))$ $=abgd$
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