Answer
$$\left[\begin{array}{ccc}{7} & {10} \\ {13} & {18}\end{array}\right].$$
Work Step by Step
Let $$
A=\left[\begin{array}{ccc}{1} & {2} \\ {3} & {4}\end{array}\right], \quad B=\left[\begin{array}{ccc}{-1} & {0} \\ {1} & {1}\end{array}\right]
$$
We have
$$2(A-B+X)=3(X-A)\Longrightarrow X=5A-2B$$
and hence $$X=5\left[\begin{array}{ccc}{1} & {2} \\ {3} & {4}\end{array}\right]-2\left[\begin{array}{ccc}{-1} & {0} \\ {1} & {1}\end{array}\right]=\left[\begin{array}{ccc}{7} & {10} \\ {13} & {18}\end{array}\right].$$
