Answer
$\begin{bmatrix}3 & 3 \\19 & 27\end{bmatrix}$
Work Step by Step
We have: $D+BC=\begin{bmatrix}0 & -3\\-2 & 1\end{bmatrix}+\begin{bmatrix}4 & -2 & 1\\0 & 2 & 3\end{bmatrix} \cdot \begin{bmatrix}1 & 2\\3 & 4 \\ 5 & 6\end{bmatrix} $
$=\begin{bmatrix}0 & -3\\-2 & 1\end{bmatrix}+\begin{bmatrix}4-6+5 & 8-8+6 \\ 0+6+15 & 0+8+18 \end{bmatrix}$
After simplification, we obtain:
$=\begin{bmatrix}3 & 3 \\19 & 27\end{bmatrix}$