Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 3 - Matrices - 3.1 Matrix Operations - Exercises 3.1 - Page 152: 12

Answer

$$EF=\left[\begin{array}{ll}{0} \end{array}\right].$$

Work Step by Step

Since $$ E=\left[\begin{array}{ll}{4} & {2}\end{array}\right], \quad F=\left[\begin{array}{r}{-1} \\ {2}\end{array}\right] $$ we have $$EF= \left[\begin{array}{ll}{4} & {2}\end{array}\right] \left[\begin{array}{r}{-1} \\ {2}\end{array}\right]=\left[\begin{array}{ll}{0} \end{array}\right].$$
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