Answer
$\frac{y^2}{2}-\frac{1}{3}log(x^3+1)+c=0$
Work Step by Step
$\frac{dy}{dx}=\frac{x^2}{y(1+x^3)}$
Separate variables
$y(1+x^3)dy=x^2dx$
$\int{ydy}=\int{\frac{x^2}{1+x^3}dx}$
$\frac{y^2}{2}-\frac{1}{3}log(x^3+1)+c=0$
Elementary Differential Equations and Boundary Value Problems 9th Edition
by Boyce, William E.; DiPrima, Richard C.
Published by
Wiley
ISBN 10:
0-47038-334-8
ISBN 13:
978-0-47038-334-6
Chapter 2 - First Order Differential Equations - 2.2 Separable Equations - Problems - Page 47: 2
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