#### Answer

$\frac{y^2}{2}-\frac{1}{3}log(x^3+1)+c=0$

#### Work Step by Step

$\frac{dy}{dx}=\frac{x^2}{y(1+x^3)}$
Separate variables
$y(1+x^3)dy=x^2dx$
$\int{ydy}=\int{\frac{x^2}{1+x^3}dx}$
$\frac{y^2}{2}-\frac{1}{3}log(x^3+1)+c=0$

Published by
Wiley

ISBN 10:
0-47038-334-8

ISBN 13:
978-0-47038-334-6

$\frac{y^2}{2}-\frac{1}{3}log(x^3+1)+c=0$

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