University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter Appendices - Section A.3 - Lines and Circles - Exercises - Page AP-15: 3

Answer

The unit circle.

Work Step by Step

The LHS can be written as $(x-0)^{2}+(y-0)^{2}$, which is the square of the distance of the point $(x,y)$ from the origin, $(0,0)$. So, the distance of all these points from the origin is equal to the square root of the RHS, which is 1. This set of points is a circle, centered at the origin, with radius 1. We call this circle the unit circle. --- Alternatively, we could have compared the given equation to Equation (1) in the text, $(x-h)^{2}+(y-k)^{2}=r^{2}$ the standard equation for a circle of radius $r,$ centered at $(h,k)$, and arrived to the same answer: the unit circle.
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