University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter Appendices - Section A.3 - Lines and Circles - Exercises - Page AP-15: 19

Answer

$(x_{2},y_{2})=(3,-3)$

Work Step by Step

We find the second pair of coordinates: $(x_{1},y_{1})=(-2,3),\quad$ $(x_{2},y_{2})=$... $\left\{\begin{array}{l} \Delta x=x_{2}-x_{1}=5\\ \Delta y=y_{2}-y_{1}=-6 \end{array}\right.$ $\left\{\begin{array}{l} x_{2}=5+x_{1}=5+(-2)=3\\\\ y_{2}=y_{1}+(-6)=3-6=-3 \end{array}\right.$ $(x_{2},y_{2})=(3,-3)$
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