University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.7 - Power Series - Exercises - Page 531: 40

Answer

Radius of convergence is $e$.

Work Step by Step

We need to apply the Root Test to the series. $L=\lim\limits_{n \to \infty} |a_n|^{1/n}=|x| \lim\limits_{n \to \infty} (\dfrac{n}{n+1})^n$ or, $=|x| \lim\limits_{n \to \infty} \dfrac{n+1}{8n+4}$ or, $=|x| \lim\limits_{n \to \infty} \dfrac{1}{e}$ or, $=\dfrac{1}{e}|x|$ Now, $\dfrac{1}{e}|x| \lt 1 \implies |x| \lt e$ Thus, the radius of convergence is $e$.
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