Answer
$2 \times 10^{-11}$
Work Step by Step
We have $S_n=a_1-a_2+......+(-1)^{n+1}a_n$
Now, $|S-S_n|=\leq |a_{n+1}|$
So, $|\space Error |=|S-S_4| \leq |a_{4+1}|=|a_5|$
or, $=|(-1)^6 \times (\dfrac{0.01}{5})^5|$
or, $=2 \times 10^{-11}$