## University Calculus: Early Transcendentals (3rd Edition)

Consider $u_n=(-1)^{n+1}(0.1)^n$ Here, $u_n$ is positive for all the values of $n$. and $|u_n|=(0.1)^n$ Thus, the series $\Sigma_{n=1}^\infty |u_n|$ is a convergent geometric series with $r=0.1$ Hence, the series converges absolutely.