University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.4 - Comparison Tests - Exercises - Page 509: 56



Work Step by Step

We are given that $\Sigma a_n$ is convergent. Since, we have $\Sigma \dfrac{a_n}{n} \lt \Sigma a_n$ Thus, the series is less than a convergent series and thus is also convergent. Hence, the given series $\Sigma \dfrac{a_n}{n}$ is convergent.
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