University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.4 - Integration of Rational Functions by Partial Fractions - Exercises - Page 446: 39

Answer

$$\int\frac{e^tdt}{e^{2t}+3e^t+2}=\ln|e^t+1|-\ln|e^t+2|+C$$

Work Step by Step

$$I=\int\frac{e^tdt}{e^{2t}+3e^t+2}$$ Set $u=e^t$, which means $$du=e^tdt$$ Therefore, $$I=\int\frac{du}{u^2+3u+2}$$ $$I=\int\frac{du}{(u+1)(u+2)}$$ $$I=\int\frac{(u+2)-(u+1)}{(u+1)(u+2)}du$$ $$I=\int\frac{du}{u+1}-\int\frac{du}{u+2}$$ $$I=\ln|u+1|-\ln|u+2|+C$$ $$I=\ln|e^t+1|-\ln|e^t+2|+C$$
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