Answer
$5 \cosh(\dfrac{ x}{5})+C$
Work Step by Step
Given: $\int \sinh (\dfrac{x}{5}) dx$
Use the identity: $\int \sinh x dx=\cosh x +C$
Thus, $\int \sinh (\dfrac{x}{5}) dx=\dfrac{ \cosh(\dfrac{ x}{5})}{1/5}+C= 5 \cosh(\dfrac{ x}{5})+C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 7 - Section 7.3 - Hyperbolic Functions - Exercises - Page 418: 42
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