University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Section 7.3 - Hyperbolic Functions - Exercises - Page 417: 17

Answer

$\coth z$

Work Step by Step

Since, $\dfrac{d}{dx} (\sinh x)=cosh x$ As we are given that $y=\ln (\sinh z)$ Then, on differentiating , we have: $\dfrac{dy}{dz}= (\cosh z) \dfrac{1}{\sinh z} =\coth z$
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