Answer
$\cosh (2x+1)$
Work Step by Step
Since, $\dfrac{d}{dx} (\cosh x)=\sinh x$
As we are given that $y=\dfrac{1}{2} \sinh (2x+1)$
Then, on differentiating , we have
$\dfrac{dy}{dx}= \dfrac{1}{2} \cosh (2x+1) (2)= \cosh (2x+1)$
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